Ayuda con el problema integral definitivo. ¡Gracias!
Fórmula original = (1/9) ∫ (√(x 9) √x ) dx
= (1/9) * (2/3) { [(x 9 )^(3/2) x^(3/2)] | (x=16) - [(x 9)^(3/2) x^(3/2)] | p>
= (2/27) ( 125 64 - 27)
= 12
Fórmula original = (1/9) ∫ (√(x 9) √x ) dx
= (1/9) * (2/3) { [(x 9 )^(3/2) x^(3/2)] | (x=16) - [(x 9)^(3/2) x^(3/2)] | p>
= (2/27) ( 125 64 - 27)
= 12